Then we construct a full beginner with indexes, which takes the value of one pupil created by the item
to relax on each iteration of key starts as a blank string and the for loop iterate.
So the individuals from zero up to but not including the most likely killing the Woodhill for each duplicate
constructor.
Now as the eye variable, now as the variable changes for each iteration for the for loop, the loop
and the indexes and the index eye is the index of people we want to use in all frequency score which
is over here.
So this is why the all frequency, cause I add the indexes, i.e. returns or evaluates the correctable
we want, when we want or when we have the correctible we need to access index zero at the tuple to
get this up.
Now, if the silent mode over here is false, then it is the key that was created by the for loop on
this particular line in the print statement.
Now that we have a complete beginner key to decrypt these ciphertext and check whether the decrypted
text is readable English, if it is the program principal the screen for the user to confirm that it
is in English to check for the false positives.
So then we have the printing, the decrypted text with the correct casing.
So over here, because the decrypted text that we are getting here is in the uppercase.
We build a new string by opening and uppercase lowercase form of letters in the decrypted text to the
original case list.
So if we just see this particular program, default loop over here goes through the each of the indexes
in the ciphertext string, which unlikely ciphertext up has an original casing of the ciphertext.
And if the ciphertext at the index using the uppercase, then the uppercase form of the decrypted text
is upended.
Otherwise I.
Lorqess form of the decrypted text is appended.
So the list in the original case is then joined on to become a new value when the decrypted text.
So the next line of the code brings the decryption output to the user could check whether the key has
been found.
So we are giving this print commands to the user next, which is basically printing the correctly based
decrypted text is printed on the screen for user to confirm it is English.
If the user enters the function, returns decrypted text string.
Otherwise, if none of the decryption looks like English hacking has failed and non-value is returned
at the end of this particular method now coming to returning the hacked message.
Now, finally, all of the functions that we have defined will be used by the Hack Virginia function,
which accepts a ciphertext string as an argument and return the hacked message if hacking was successful
or not.
If it wasn't, it starts by getting the likely killens with ASCII examination function.
So if you come at this particular function here, that is hack in your function in this V so defined
that the output depends on whether the program is in the silent mode.
So the likely killens are then printed to the screen.
If the silent mode is off, it checks over here.
Next, we need to find likely some letters for each Gilan.
We will do that with another loop that attempts to have this Saiful with each Elance we found then breaking
out of the loop when the potential is found.
So we want the code to continue looping and checking the Queenland until it finds a potential correct
chelate.
So then it finds the killing.
That seems correct.
We will stop the loop with a statement there and similar to how continual statement is used to that
is inside a loop to go back to the loop and start again.
The break statement in this is that we have used Volks program execution breaks out of a loop.
It immediately moves to the first line of core after the loop ends, so will break out of the loop whenever
the program finds a potential correct.
E I need to ask the user to confirm the keys.
Correct.
So over here, for each possible Chelin, the code calls your attempt back with Keelen function, which
is over here.
And if the attempt with Ealand does not return, the hack is successful and program execution should
break out of the default loop.
Hence we have break it all with you now coming to the brute force, all other fields.
Now, if the hack fills all the possible killens that didkovsky examinations with done Hackman's, they
just said to null.
And if the if statement executes overfield, then all the other commands to Max Eland are right.
And if Kosofsky examination fails to calculate the correct chelate, we can just brute force through
the equivalent of the fourth loop over here, which is the for loop we have done here.
And after that we start with the for loop in the statement for each value of your helan.
That's here for killing in the range, which ranges from one to the max, as long as it's not in the
unlikely.
And the reason is that the killing in all likely killings have already been tried in the earlier court.
So finally, we have completed the loop and then we return the message, a step function after executing
it after this particular function.
The only thing that remains is calling this main function.
So if this program was run by itself rather than being imported by another program.
So the full vaginalis hacking program that we have seen, whether it's successful, depends on the characteristics
of the ciphertext.
The closer the original plaintext little frequency is to regular English little frequency and longer
the plaintext, the more likely the hacking program will work.
Now, modifying the constant of the hacking program that we have defined in the beginning of the program
here, we can modify a few details of the hacking program, doesn't work this book and we will not do
it over here.
But in your case, if it is not working, then the constants we set over here that affect how the hacking
program runs, say, for example, this max length over here is 16 will not attempt this longer than
this.
So you can change this if you want to try it somewhere else.
On the most frequency letters, which we have given here for all the silent mode which we have given
this Foote's.
So if the beginner key is longer than the key in the max of Ealand, there is no way the hacking program
will find the correct key.
So if the hacking program fails to have the ciphertext try increasing this value and running the program
again.
Also, keep in mind that trying to hack an incorrect Chelin that is short takes a short amount of time.
But if the max scale in this set very high, the kazatsky examination function mistakenly thinks that
the KMD could be an enormous ILIJA program, could spend hours or even months attempting to hack a particular
ciphertext to prevent this dynamo's frequency, let those limits the number of possible tries for it.
By increasing this value, the hacking program tries many more keys, which you might need to do if
the frequency analysis or English frequency Matkal was inaccurate.
But this also causes the program to slow down and in the most frequency that those three point six would
cause the program to skip, narrowing down the number of possibilities for each piece.
So for both the max and the most frequency that those are smaller value is faster to execute, but less
likely to succeed in hacking a cipher and a larger value secured but more likely to succeed.
So finally, to increase the speed of your program, you can say this silent more SDR to do so.
The program doesn't waste time printing information to the screen.
Although your computer can perform calculations quickly, displaying characters on screen can be relatively
slow.
The downside of not printing information is that you won't know how the program is doing until it has
completely finished running.
So with this, we have completed the original hiking demo with a complete understanding of how the particular
program executes.
That is the end of our beginner hacking demo session.
Thank you very much.