We are going to encode our code with detector operation, right, so the need for an inner circle is
the most enduring tourists.
This will have this Bindschadler, Churchill or any other circular pattern in their databases.
And whenever this record has been.
Written on the table, or if that has been executed on the commission designed to resist my triggering
alarm.
So the databases of those and others contain this pattern of the outer circle.
So if we encode that circle, then it may be chances for some antivirus to help bypass.
And we don't need to bypass every antivirus in the world, but we need to bypass only the software of
the current system.
Right.
You know, if you are checking in with him or any testing in a crime organization, you need to know
about what I noticed.
There is obviously do not use every antivirus in the world, but there use one or two.
Right.
If your circle bypasses those two antivirus software, then you will obviously will win the game.
Right now, I have a picture of the current president I shall call visible when I am anchoring with
this Shakoor.
I have got some issues because of this rash X.
It's representing disaster as a matter of course it should represent.
But some characters are turning into Unicode characters.
That's what I heard on this.
I am going to replace this Brack's backslash with null.
I won't.
I'm going to remove this backsliders so don't worry.
Yes, we get the circle in line for my country.
OK, this is our thing now.
We need to remove the X right there.
We know there is no X in the hexadecimal system, no system.
Right CareMore X.
We need to look for this and telescreen to do that so far.
OK, first we will make the string.
In order to do that, there is a function that's a hex underscore Dom is equal to.
This toucher.
So if I put in that accident.
Now, I look at each and every character in the new element of every stripe.
Now we can just simply look over it and remove the eggs for I in the hexagram.
If I is equal, is equal to X, then we need to say X dump the rule of it right now.
Let me cut this statement and pasted in here.
Now we can see there is no X.
Perfect, there is 31 C0 and I get 31 and be perfect.
Now, why do we need to join?
We need to join these two elements as one singular.
It's spring and these two are single spring, and these two, as soon as she saw the output should be
31.
Come on, come on, baby, that and 31 on and so on up to this last twenty eight.
So we need to just concatenate these two or append these two characters into one thing to do that let's
we are going to cover us and we're going to report the I in now we loop or this range of come up and
Lentulov.
Hextall.
And I will skip two characters because in one step I happened, all those two characters say so the
system is equal to.
I'm going to use the joint matter joint of this joint will joint the two characters specified in the
argument.
So hex dump of.
I used to I pressed to see what this.
I used three and I press one is one and it was exclusive.
So I guess I used to Hyperscore means when I used it becomes ectomorph zero is to do so in least it
is one element.
So we won't take two as into consideration because it is crazy.
So ministry one minute one and we are going to join this into the template.
Now I just simply a start up end of camp.
Now, if I put into this, as we shall see.
Correct me, commentor this one.
So if I just let you get this, OK, we have got exactly Fastback in one street and second in second
and third debate in the third place.
Right now, what we're going to do is we are going to take a first bite and then we are going to start
with a bite given in their input.
So we have value is equal to the input of.
So here we give the input and it will be stored in a value variable, that input will be provided and
that by the expert with each byte in this circle and then the output, the circle.
So here there is one problem if you exclude the same bike, you're getting out of it, right?
We are using the scumbag's and the previous use to get rid of the content suffix and its content Norbert's
so in the same way we need to enter a value that is not in this code already, because if there is to
C0, then if we exclude c0 common C0, then you get the resultant Circo.
How the nailbiter displays and the strong opposition parties decide to remove this and it will just
ignore all this content after that nabay.
So that's what we need to check the value, whether it's in Chalco or not.
To do that we need to see if.
Value in charcoaled.
So just to separate, OK, the value is in already charcoaled, we need to ask again, right?
I mean, you need to take the input again with different, but.
So it's a it is already initial to the.
So you want to sound right?
I'm going to copy this one, I'm going to put it in here.
So, again, we'll ask for the user input, and that will be widely available.
All right.
Now we have got this where you saw this value and our interest.
And in that, we need to loop over each element so that so far I in s we need to certain physicals to
know we want to convert this to turn into integer and this bit into integer and that we need to do or.
So to convert the hexadecimal in to integer into Ikoma 16 and the saw operation in Python is this is
chapter marker, just cap and tax value, comma 16.
So we are changing the hexadecimal representations in two integers and performing the exact operation
that's Encoder Shirker or just the result.
And I'm going to take that notion, so I'm going to appeal this very similar this result with.
I'm sorry, I did not do one thing, so what I want to do is we need to convert this into hexadecimal
format and to.
Haqq subcamp.
So no.
What has been committed here and then we cannot get the result of into the exodus and then we opened
it to the street.
Now let's go and bring this result.
So let's go and execute our script.
No, I learned to do that, but yeah.
So, yes, we have got this charcoaled you can see Droits nine six tonight and we OK find no we don't
want do X, so that's this one and each consists of.
So we need to avoid that is jewelries.
And actually the second element in that screen and when you say to you.
So from that element onwards we are we want to happen to the result.
So let's let's run our script and execute year.
And they realize we have got exactly nine B sixty six year, nine one nine B, etc..
So let's also put six.
I'm putting the All Blacks rush to escape this backslash special value.
So let's run this year and then realize this is our uncoded circle.
Now we need to check whether our result is character.
So open the calculator or to at least take the first bite of the ordinary circuit, which is 31.
So I go to hexadecimal and then take the first word of circle, which is 31 31, and I'm going to ignore
it.
So what we have input this year.
You know, if you hit enter, you get the 90, which is the first.
But in the similar case, you can check the which is C zero G zero X are you and you get the value Cixi
so that this is our required and codeshare when we have done the Exaro operation between each byte shall
call with the input value.